Integrand size = 15, antiderivative size = 105 \[ \int \frac {x^6}{\sqrt [4]{a+b x^4}} \, dx=-\frac {a x^3}{4 b \sqrt [4]{a+b x^4}}+\frac {x^3 \left (a+b x^4\right )^{3/4}}{6 b}-\frac {a^{3/2} \sqrt [4]{1+\frac {a}{b x^4}} x E\left (\left .\frac {1}{2} \cot ^{-1}\left (\frac {\sqrt {b} x^2}{\sqrt {a}}\right )\right |2\right )}{4 b^{3/2} \sqrt [4]{a+b x^4}} \]
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Time = 0.03 (sec) , antiderivative size = 105, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.400, Rules used = {327, 316, 287, 342, 281, 202} \[ \int \frac {x^6}{\sqrt [4]{a+b x^4}} \, dx=-\frac {a^{3/2} x \sqrt [4]{\frac {a}{b x^4}+1} E\left (\left .\frac {1}{2} \cot ^{-1}\left (\frac {\sqrt {b} x^2}{\sqrt {a}}\right )\right |2\right )}{4 b^{3/2} \sqrt [4]{a+b x^4}}+\frac {x^3 \left (a+b x^4\right )^{3/4}}{6 b}-\frac {a x^3}{4 b \sqrt [4]{a+b x^4}} \]
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Rule 202
Rule 281
Rule 287
Rule 316
Rule 327
Rule 342
Rubi steps \begin{align*} \text {integral}& = \frac {x^3 \left (a+b x^4\right )^{3/4}}{6 b}-\frac {a \int \frac {x^2}{\sqrt [4]{a+b x^4}} \, dx}{2 b} \\ & = -\frac {a x^3}{4 b \sqrt [4]{a+b x^4}}+\frac {x^3 \left (a+b x^4\right )^{3/4}}{6 b}+\frac {a^2 \int \frac {x^2}{\left (a+b x^4\right )^{5/4}} \, dx}{4 b} \\ & = -\frac {a x^3}{4 b \sqrt [4]{a+b x^4}}+\frac {x^3 \left (a+b x^4\right )^{3/4}}{6 b}+\frac {\left (a^2 \sqrt [4]{1+\frac {a}{b x^4}} x\right ) \int \frac {1}{\left (1+\frac {a}{b x^4}\right )^{5/4} x^3} \, dx}{4 b^2 \sqrt [4]{a+b x^4}} \\ & = -\frac {a x^3}{4 b \sqrt [4]{a+b x^4}}+\frac {x^3 \left (a+b x^4\right )^{3/4}}{6 b}-\frac {\left (a^2 \sqrt [4]{1+\frac {a}{b x^4}} x\right ) \text {Subst}\left (\int \frac {x}{\left (1+\frac {a x^4}{b}\right )^{5/4}} \, dx,x,\frac {1}{x}\right )}{4 b^2 \sqrt [4]{a+b x^4}} \\ & = -\frac {a x^3}{4 b \sqrt [4]{a+b x^4}}+\frac {x^3 \left (a+b x^4\right )^{3/4}}{6 b}-\frac {\left (a^2 \sqrt [4]{1+\frac {a}{b x^4}} x\right ) \text {Subst}\left (\int \frac {1}{\left (1+\frac {a x^2}{b}\right )^{5/4}} \, dx,x,\frac {1}{x^2}\right )}{8 b^2 \sqrt [4]{a+b x^4}} \\ & = -\frac {a x^3}{4 b \sqrt [4]{a+b x^4}}+\frac {x^3 \left (a+b x^4\right )^{3/4}}{6 b}-\frac {a^{3/2} \sqrt [4]{1+\frac {a}{b x^4}} x E\left (\left .\frac {1}{2} \cot ^{-1}\left (\frac {\sqrt {b} x^2}{\sqrt {a}}\right )\right |2\right )}{4 b^{3/2} \sqrt [4]{a+b x^4}} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 7.35 (sec) , antiderivative size = 64, normalized size of antiderivative = 0.61 \[ \int \frac {x^6}{\sqrt [4]{a+b x^4}} \, dx=\frac {x^3 \left (a+b x^4-a \sqrt [4]{1+\frac {b x^4}{a}} \operatorname {Hypergeometric2F1}\left (\frac {1}{4},\frac {3}{4},\frac {7}{4},-\frac {b x^4}{a}\right )\right )}{6 b \sqrt [4]{a+b x^4}} \]
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\[\int \frac {x^{6}}{\left (b \,x^{4}+a \right )^{\frac {1}{4}}}d x\]
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\[ \int \frac {x^6}{\sqrt [4]{a+b x^4}} \, dx=\int { \frac {x^{6}}{{\left (b x^{4} + a\right )}^{\frac {1}{4}}} \,d x } \]
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Result contains complex when optimal does not.
Time = 0.50 (sec) , antiderivative size = 37, normalized size of antiderivative = 0.35 \[ \int \frac {x^6}{\sqrt [4]{a+b x^4}} \, dx=\frac {x^{7} \Gamma \left (\frac {7}{4}\right ) {{}_{2}F_{1}\left (\begin {matrix} \frac {1}{4}, \frac {7}{4} \\ \frac {11}{4} \end {matrix}\middle | {\frac {b x^{4} e^{i \pi }}{a}} \right )}}{4 \sqrt [4]{a} \Gamma \left (\frac {11}{4}\right )} \]
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\[ \int \frac {x^6}{\sqrt [4]{a+b x^4}} \, dx=\int { \frac {x^{6}}{{\left (b x^{4} + a\right )}^{\frac {1}{4}}} \,d x } \]
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\[ \int \frac {x^6}{\sqrt [4]{a+b x^4}} \, dx=\int { \frac {x^{6}}{{\left (b x^{4} + a\right )}^{\frac {1}{4}}} \,d x } \]
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Timed out. \[ \int \frac {x^6}{\sqrt [4]{a+b x^4}} \, dx=\int \frac {x^6}{{\left (b\,x^4+a\right )}^{1/4}} \,d x \]
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